The bond energy of H_(2) is foundto be 435 kJ mol^(-1). Therefore, the enthalpy of formation of hydrogen atom will be "…................"

The bond energy of H_(2) is foundto be 435 kJ mol^(-1). Therefore, the

1.	The bond energy of H_(2) is foundto be 435 kJ mol^(-1). Therefore, the enthalpy of formation of hydrogen atom will be "…................"
Answer» SOLUTION : `435 //2 = 217.5 KJ MOL^(-1)`