The bond enthalpies of D-D and 0-0 and D - ( are respectively, + 440, + 498 and + 491.5 kJ mol^(-1). Calculate DeltaH for the reaction D _(2 (g)) + (1)/(2) O _(2(g)) to D _(2) O _((l))

The bond enthalpies of D-D and 0-0 and D - ( are respectively, + 440,

1.	The bond enthalpies of D-D and 0-0 and D - ( are respectively, + 440, + 498 and + 491.5 kJ mol^(-1). Calculate DeltaH for the reaction D _(2 (g)) + (1)/(2) O _(2(g)) to D _(2) O _((l))
Answer» SOLUTION :Heat of reaction, `DeltaH = `(Enthalpy of bonds dissociated) - (Enthalpy of bonds formed) `Delta H = (440 + (498)/(2)) - (2 xx 491 .5)` `=689-983 =-294 KJ` Enthalpy of the GIVEN reaction is `- 294 kJ .`