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The bond enthalpies of D-D and O-O and D-O are respectively +440 ,+498 and +491.5KJ "mol"^(-1) calculation Delta H for the reaction D_(2)(g) +1/2O_(2)(g)to D_(2) O(l) |
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Answer» SOLUTION :Heat of REACTION, =(Enthalpy of bonds DISSOCIATED )-(Enthalpy of bonds formed) `DELTA H=(440+498/2)-(2xx491.5)=689-983=-294KJ` Enthalpy of the given reaction is -294KJ. |
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