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The bond order in N2 molecule is …………(A) 1 (B) 2 (C) 3 (D) 4 |
Answer» Correct Option is : (C) 3 Molecular Configuration of \(N_2\) \( 15 \sigma^2 \ 15 \sigma^{\ast 2} \ 25 \sigma^2 \ 15 \sigma^{\ast 2} \ 2p_x \sigma^2 \ 2p_y \pi^2 = 2p_z{\pi^2}\) Bond Order = \(\frac{bonding \ e^- \ - \ antibonding \ e^- }{2}\) = \(\frac{10-4}{2}\) = 3 Option : (C) 3 |
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