1.

The bond order in \(O_2^{2-}\) is

Answer»

Bond order (B.O) = \(\frac{1}{2}\) × [Number of an electron in antibonding molecular orbitals] – [Number of electrons in bonding molecular orbitals]

B.O for O22- = \(\frac{1}{2}\) × [10 – 8] = \(\frac{1}{2}\) × 2

B.O for O22- = 1



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