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The Boolean expression `P+bar(P)Q`, where P and Q are the inputs of the logic circuit, representsA. AND gateB. NAND gateC. NOT gateD. OR gate |
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Answer» Correct Answer - D We draw a truth table for the expression `P+bar(P).Q` as given below `|{:(P,Q,bar(P),bar(P).Q,P+bar(P.Q)),(0,0,1,0,0),(0,1,1,1,1),(1,0,0,0,1),(1,1,0,0,1):}:|` We note that output is `1` when either of the input is `1`. Thus the logic circuit works as OR gate. |
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