1.

The Boolean expression `~(pvvq)vv(~p^^q)` is equivalent to (1) `~p` (2) `p` (3) `q` (4) `~q`A. `pwedge (~q)`B. `p vee(~q)`C. `(~p) wedge (~q)`D. `p wedge q`

Answer» Correct Answer - C


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