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The breaking force of wire is `10^(4)`N and radius is `1xx10^(-3)`m. If the radius is `2xx10^(-3)`m, then the breaking force will beA. `4xx10^(4)N`B. `40xx10^(4)N`C. `0.04xx10^(4)N`D. `0.4xx10^(4)N` |
Answer» Correct Answer - A `(F_(2))/(F_(1))=((r_(2))/(r_(1)))^(2)=((2xx10^(-3))/(1xx10^(-3)))^(2)=4` `F_(2)=4F_(1)` `=4 xx 10^(4)N`. |
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