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The % by volume of `C_(4)H_(10)` in a gaseous mixture of `C_(4)H_(10), CH_(4)` and `CO_(2)` is 40. When 200 ml of this mixture is burnt completely in excess of `O_(2)` and then pass through aq. KOH then volume contraction will be -A. 220 mlB. 340 mlC. 440 mlD. 560 ml |
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Answer» Correct Answer - C `ubrace(C_(4)H_(10), CH_(4),CO_(2))_("200 mL")` `C_(4)H_(10) = 0.4 xx 200 = 80 ml` `CH_(4) = x ml` `CO_(2) = (120 - x) ml` `C_(4)H_(10) + (13)/(2) O_(2) rarr 4CO_(2) + 5H_(2)O` `{:(80 ml,," 320 ml",),(CH_(4) + 2O_(2),rarr,CO_(2) + 2H_(2)O,),(x ml,,x ml,):}` Total `CO_(2) = 320 + x + 120 - x` `= 440 ml` |
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