The `C -C` bond length is `1.54 Å C =C` bond length is `1.33 Å` What is the circumference of benzene ring ? Bond length between single and double bonds `= 1.4 Å` .A. `(3 xx 1.54 + 3 xx 1.33) Å`B. `(4 xx 1.54 + 2 xx 1.33) Å`C. `(6 xx 1.4)Å`D. `(4 xx 1.33 +2 xx 1.54)Å`

The `C -C` bond length is `1.54 Å C =C` bond length is `1.33 Å` What

1.	The `C -C` bond length is `1.54 Å C =C` bond length is `1.33 Å` What is the circumference of benzene ring ? Bond length between single and double bonds `= 1.4 Å` .A. `(3 xx 1.54 + 3 xx 1.33) Å`B. `(4 xx 1.54 + 2 xx 1.33) Å`C. `(6 xx 1.4)Å`D. `(4 xx 1.33 +2 xx 1.54)Å`
Answer» Correct Answer - C Due to resonance the `C -C` bond length in benzyne is in between single and double bonds `1.4Å` Hence circumference ` = 6 xx 1.4 Å` .

Discussion

No Comment Found

Related InterviewSolutions

Statement-1 : `NH_(3)` is pyramidal in shape . Statement-2 : `SiCl_(4)` and `GaCl_(4)^(-)` are isostructural . Statement-3 : `sd^(3)` hybridisation may be possibleA. TTFB. TTTC. FTTD. TFT
`O_(2)` and `N_(2)` are respectivelyA. Diamagnetic , ParamagneticB. Paramagnetic , DiamagneticC. Both the paramagneticD. Both are diamagnetic
Molecular shape of `ClF_(3) , l_(3)^(-)` and `XeO_(3)` respectively areA. T-shape , Linear , PyramidalB. Planar , Linear , TetrahedralC. T-shape , Planar , PyramidalD. Trigonal bipyramidal , Linear , Tetrahedral
In case of `XeO_(2) F_(2)` and `XeF_(6)` , Xe is withA. Same hybridization but with different geometryB. Different hybridization with same geometryC. Different hybridization and different geometryD. Same geometry and same hybridization
The shapes of `XeO_(2)F_(2)` molecule isA. trigonal bipyramidalB. square planarC. tetrahedralD. see-saw.
Which is the correct arrangement of the molecules basexd on dipole moments ?A. `BF_(3) = NH_(3) = NF_(3)`B. `BF_(3) gt NH_(3) gt NF_(3)`C. `BF_(3) lt NH_(3) lt NF_(3)`D. `BF_(3) lt NF_(3) lt NH_(3)`
Which one of the following arrangements of molecules is correct on the basis of their dipole moments ?A. `BF_(3) gt NF_(3) NH_(3)`B. `NF_(3) gt BF_(3) gt NH_(3)`C. `NH_(3) = NF_(3) gt BF_(3)`D. `NH_(3) gt NF_(3) gt BF_(3)`
The crystal lattice of electro covalent compounds is composed ofA. AtomsB. MoleculesC. Oppositely charged ionsD. Both molecules and ions
Statement 1 : All molecules with polar bonds may not have dipole moments Statement 2 : Dipole moment is a vectot quantity and bond dipoles may cancel out.A. Statemetn-1 is true, Statrment-2 is also true, Statement -2 is the correct explanation of statement-1B. Statement -1 is true , Statement 2 is also true, Statement-2 is not the correct ezplanation of Statement-1C. Statement-1 is true, Statement-2 is false.D. Statement-1 is false, Statement-2 is true.
The crystal lattice of electro covalent compounds is composed ofA. atomsB. moleculesC. oppositeoly charged ionsD. both molecules and ions.

The `C -C` bond length is `1.54 Å C =C` bond length is `1.33 Å` What is the circumference of benzene ring ? Bond length between single and double bonds `= 1.4 Å` .A. `(3 xx 1.54 + 3 xx 1.33) Å`B. `(4 xx 1.54 + 2 xx 1.33) Å`C. `(6 xx 1.4)Å`D. `(4 xx 1.33 +2 xx 1.54)Å`

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment