The calculations of the length of the edge of the cube and the distance between (100) planes in case of NaCl crystal is possible after knowingmolecular weight and Avogadro's numberb) molecular weight and densityc) density and Avogadro's numberd) inolar volume and Avogadro's number

The calculations of the length of the edge of the cube and the distanc

1.	The calculations of the length of the edge of the cube and the distance between (100) planes in case of NaCl crystal is possible after knowingmolecular weight and Avogadro's numberb) molecular weight and densityc) density and Avogadro's numberd) inolar volume and Avogadro's number
Answer» DENSITY of NACL =2.165 g/ccNumber of atoms in NaCl =4 FCC STRUCTURE r Na + +R Cl − = 2a 281=0.3535 a⇒a=794.9 PM =794.9×10 −10 cmMolecular weight of NaCl =23+35.5=58.5 g/mold= a 3 ×N A z×m 2.165= (794.9×10 −10 ) 3 ×N A 4×58.5 N A = (794.9×10 −10 ) 3 ×2.1654×58.5 N A =6.09×10 23 Hence, the value of the avogadro's number is 6.09×10 23 .Explanation:i hope it helps you