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The capacitance between the points `A` and `B` in the given circuit will be A. `3.5muF`B. `3muF`C. `2muF`D. `1muF` |
Answer» Correct Answer - D `C_(1)=3muF,C_(2)=C_(3)=1.5muF,C_(4)=3muF,C_(PQ)=?` Now `C_(P)=C_(2)+C_(3)=1.5+1.5=3muF` Now `C_(1), C_(P) and C_(4)` are in series `1/C_(s)=1/C_(1)+1/C_(p)+1/C_(4)=1/3+1/3+1/3` `C_(s)=C_(PQ)=1muF` |
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