1.

The capacitance of a parallel-plate air capacitor is 2 pF. If the air is replaced by a medium of dielectric constant 10. What will be its capacitance?

Answer»

\(\cfrac{C_2}{C_1}\) = \(\cfrac{k_2}{k_1}\)

C2\(\cfrac{k_2}{k_1}\) x C1\(\cfrac{10}1\) x 2 = 20 pF

is the required capacitance.



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