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The capacity of a parallel plate air capacitor is `10muF` and it is given a charge of `40muC`. The electrical energy stored in the capacitor isA. 400 ergB. 600 ergC. 800 ergD. 900 erg |
Answer» Correct Answer - C `E=Q^(2)/(2C)=((40xx10^(-6))^(2))/(2xx10xx10^(-6))` `=80xx10^(-6)J` = 800 erg. |
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