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The capacity of a parallel plate air capacitor is `2 mu F` and voltage beteen the plates is changing at the rate of 3 v/s the displacement current in the capacitor isA. `2 muA`B. `3 mu A`C. `5 muA`D. `6 muA` |
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Answer» Correct Answer - a The displacement current can be found as displacement current = conduction current `I_(d) =(d)/(dt)CV=c(d)/(dt)V` `I_(D)=2xx10^(-6)xxx3=6muA` |
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