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The capacity of a parallel plate condenser is `12muF`. Its capacity, when the separation between plates is doubled and area is halved will beA. `3muF`B. `12muF`C. `6muF`D. `1.5muF` |
Answer» Correct Answer - A `C_(1)=12muF, C_(2)=?` If `d_(2)=2d_(1)andA_(2)=A_(1)/2` `CpropA/d` `therefore" "C_(2)/C_(1)=A_(2)/A_(1)xxd_(1)/d_(2)=A_(1)/(2A_(1))xxd_(1)/(2d_(1))=1/4` `C_(2)=C_(1)/4=12/4=3muF` |
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