The carrier freqeuncy of a station is 40 MHz. A resistor of 10k `Omega` and capacitor of 12 pF are available in the detector circuit. The possible value of C will beA. 12B. 8.2C. 5.6D. All of these

The carrier freqeuncy of a station is 40 MHz. A resistor of 10k `Omega

1.	The carrier freqeuncy of a station is 40 MHz. A resistor of 10k `Omega` and capacitor of 12 pF are available in the detector circuit. The possible value of C will beA. 12B. 8.2C. 5.6D. All of these
Answer» Correct Answer - D Here, `R=10kOmega=10xx10^(3)Omega` `C=12pF=12xx10^(-12)F` `v_(c)=40MHz=40xx10^(6)Hz=4xx10^(7)Hz`. Time period of carrier frequency `T_(c)=(1)/(v_(c))-(1)/(4xx10^(7))=2.5xx10^(8)s` time constant of C-R circuit, As `T_(c)lt tau`, therefore, circuit is good enough for detection All the values of C given in the options are possible.

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The carrier freqeuncy of a station is 40 MHz. A resistor of 10k `Omega` and capacitor of 12 pF are available in the detector circuit. The possible value of C will beA. 12B. 8.2C. 5.6D. All of these

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