InterviewSolution
Saved Bookmarks
| 1. |
The Cartesian equations of a line are `(x-2)/(2)=(y+1)/(3) =(z-3)/(-2)` .What is its vector equations ?A. `vec(r ) =(2hat(i) +3hat(j) -2hat(k)) +lambda (2hat(i) -hat(j) +3hat(k))`B. `vec(r )=(2hat(i) -hat(j) +3hat(k)) +lambda (2hat(i) +3hat(j) -2hat(k))`C. `vec(r ) =(2hat(i) +3hat(j) -2hat(k))`D. none of these |
|
Answer» Correct Answer - B The line passes through the point `(2hat(i) - hat(j) +3hat(k))` and it is parallel to the vector `(2hat(i) + 3hat(j) -2hat(k))` So, its vector equations `vec(r ) = (2hat(i) - hat(j) +3hat(k)) + lambda (2hat(i) +3hat(j) -2hat(k))` |
|