InterviewSolution
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InterviewSolution
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The ceiling of a hall is 40m high. For maximum horizontal distance, the angle at which the ball may be thrown with a speed of `56ms^(-1)` without hitting the ceiling of the hall isA. `25^(@)`B. `30^(@)`C. `45^(@)`D. `60^(@)` |
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Answer» Correct Answer - B Here, `u = 56 ms^(-1)` Let `theta` be the angle of projection with the horizontal to have maximum range, with maximum height = 40 m Maximum height, `H = (u^(2) sin^(2) theta)/(2g)` ` 40 = ((56)^(2) sin^(2) theta)/(2 xx 9.8)` `sin^(2) theta = (2xx 9.8 xx 40)/((56)^(2)) = (1)/(4) or sin theta = (1)/(2) = sin^(-1) ((1)/(2)) = 30^(@)` |
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