The cell in which the following reaction occurs: `2Fe^(3+)(aq)+2I^(-)(aq)to2Fe^(2+)(aq)+I_(2)(s)` has `E_(cell)^(@)=0.236V` at 298K. Calculate the standard Gibbs energy and the equilibrium constant of the cell reaction.

The cell in which the following reaction occurs: `2Fe^(3+)(aq)+2I^(-)(

1.	The cell in which the following reaction occurs: `2Fe^(3+)(aq)+2I^(-)(aq)to2Fe^(2+)(aq)+I_(2)(s)` has `E_(cell)^(@)=0.236V` at 298K. Calculate the standard Gibbs energy and the equilibrium constant of the cell reaction.
Answer» `2Fe^(3+)+2e^(-)to2Fe^(2+)` or `2I^(-)toI_(2)+2e^(-)` `Delta_(r)G^(@)=nFE_(cell)^(@)=-2xx96500xx0.236J=-45.55kJ" "mol^(-1)` `Delta_(r)G^(@)=-2.303RT" log "K_(c)` or `"log "K_(c)=(Delta_(r)G^(@))/(2.303RT)=(-45.55" kJ "mol^(-1))/(2.303xx8.314xx10^(-3)" kJ "K^(-1)xx298K)=7.983` `thereforeK_(c)=`Antilog `(7.983)=9.616xx10^7`

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The cell in which the following reaction occurs: `2Fe^(3+)(aq)+2I^(-)(aq)to2Fe^(2+)(aq)+I_(2)(s)` has `E_(cell)^(@)=0.236V` at 298K. Calculate the standard Gibbs energy and the equilibrium constant of the cell reaction.

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