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The cell membrane of a resting nerve in a human body has a thickness of 75 Å. If potential difference between the two sides of membrace is 0.06 V. Then intensity of electric field isA. `8xx10^(6)V//m`B. `4xx10^(6)V//m`C. `8xx10^(-6)V//m`D. `4xx10^(-6)V//m` |
Answer» Correct Answer - A `E=V/d=0.06/(75xx10^(-10))=8xx10^(6)V//m.` |
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