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The cell `Pt, H_(2) (1atm) H^(+) (pH =x)|` Normal calomel Electrode has an EMF of `0.67V` at `25^(@)C` .Calculate the pH of the solution. The oxidation potential of the calomel electrode on hydrogen scale is `-0.28V`. |
Answer» Correct Answer - `pH = 6.61` `E_(cell) = E_(cell)^(@) -(0.0591)/(1)log 10^(-x)` `0.67 =0.28 +(0.0591)/(1) xx x` `x = 6.61` |
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