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The centre of the circle inscribed in a square formed by the lines x2 - 8x + 12 = 0 and y2 -14y + 45 = 0 is(A) (4, 7)(B) (7, 4)(C) (9, 4)(D) (4, 9) |
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Answer» Correct option (a) 4,7 Explanation : The lines are x = 2, x = 6 and y = 5, y = 9. Therefore, the vertices of the square are (2, 5), (2, 9), (6, 9) and (6, 5). Centre of the circle = Centre of the square =(2 + 6/2, 9 + 5/2) = (4,7) |
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