1.

The change of energy on freezing 1.00 kg of liquidwater at 0^(@)C and1 atmis

Answer»

`236 .7 kJ KG^(-1)`
` 333.4kJ kg^(-1)`
` - 333.4kJ kg^(-1)`
`- 236 .7 kJ kg^(-1)`

SOLUTION :Enthalpy of fusion of ice `= 6.03 kJ mol^(-1)` at `0^(@)C`
`:.`Enthalpy of freezing of water `= - 6.03 kJmol^(-1) `at`0^(@)C`
i.e.,.Enthalpy change on freezing of 18 g ofwater at `0^(@)C =- 6.03 kJ`
`:.`ENTHALPYCHANGE on freezing1000 g ofwter.
`= - ( 6.03)/( 18) xx 1000 =- 335 kJ `


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