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The change of energy on freezing 1.00 kg of liquidwater at 0^(@)C and1 atmis |
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Answer» `236 .7 kJ KG^(-1)` `:.`Enthalpy of freezing of water `= - 6.03 kJmol^(-1) `at`0^(@)C` i.e.,.Enthalpy change on freezing of 18 g ofwater at `0^(@)C =- 6.03 kJ` `:.`ENTHALPYCHANGE on freezing1000 g ofwter. `= - ( 6.03)/( 18) xx 1000 =- 335 kJ ` |
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