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The charge and energy stored in the capacitor of capacity `32muF`, when it is charged to a potential difference of 0.6 kV are respectivelyA. `1.92xx10^(-2)C,5.76J`B. `2.92xx10^(-2)C,5.76J`C. `1.92xx10^(2)C,5.76J`D. `1.92xx10^(-2)C,4.76J` |
Answer» Correct Answer - A Q = CV `=32xx10^(-6)xx0.6xx10^(3)=1.92xx10^(-2)C` `E=1/2CV^(2)=(32xx10^(-6)xx(0.6xx10^(3))^(2))/2=5.76J.` |
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