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The charge density on the surface of a conducting sphere is `64xx10^(-7)C//m^(2)` and the electric intensity at a distance of 2 m from the centre of the sphere is `4pixx10^(4)N//C`. The radius of the sphere isA. 0.83 mB. 0.4 mC. 0.6 mD. 0.38 m |
Answer» Correct Answer - A `R^(2)=(Ein_(0)kr^(2))/sigma=(4pixx10^(4)xx8.85xx10^(-12)xx4)/(64xx10^(-7))` `therefore" "R=0.83m` |
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