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The charge flowing through a resistance R varies with time t as Q = at - bt2. The total heat produced in R is(a) a3R/6b(b) a3R/3b(c) a3R/2b(d) a3R/b |
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Answer» Correct Answer is:(a) a3R/6b Q = at - bt2. i = dQ dt = a - 2bt. i = 0 for t = t0 = a/ 2b, i.e., current flow from t = 0 to t = t0. The heat produced = i2R dt. for t ∈ [0, t0] |
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