1.

The charge flowing through the cell on cloing the key `k` is equal to : A. `(CV)/(4)`B. CVC. `(4)/(3)CV`D. `(3)/(4) CV`

Answer» Correct Answer - A
`C_("net") =(3)/(4) C` when key was open `q = (3)/(4) CV`
when key was closed `3C` becomes short circuited.
Net charge on `C` is now `q = CV`
`Delta q = q - q = (CV)/(4)`.


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