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The charge flowing through the cell on cloing the key `k` is equal to : A. `(CV)/(4)`B. CVC. `(4)/(3)CV`D. `(3)/(4) CV` |
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Answer» Correct Answer - A `C_("net") =(3)/(4) C` when key was open `q = (3)/(4) CV` when key was closed `3C` becomes short circuited. Net charge on `C` is now `q = CV` `Delta q = q - q = (CV)/(4)`. |
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