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The charge on `4muF` capacitor in the given circuit (in `muC`) is A. 12B. 24C. 36D. 42 |
Answer» Correct Answer - B In given figure, `C_(1)=4muF and C_(2)=C_(P)=6muF` are in series. `V_(1)=(C_(2)/(C_(1)+C_(2)))V=(6/(4+6))10=6V` Now`" "Q=CV=4xx10^(-6)xx6=24xx10^(-6)C` `=24muC` |
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