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The charge on a capacitor decreases η times in time t, when it discharges through a circuit with a time constant τ.(a) t = ητ(b) t = τ ln η(c) t = τ(ln η - 1)(d) t = τ ln (1 - 1/η) |
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Answer» Correct Answer is: (b) t = τ ln η Q = Q0 e -t/τ = Q0/η or e -t/τ 1/η or et/τ = η or t/τ = ln η. |
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