Related InterviewSolutions

• The wavelength of X-rays isA. 2000 ÅB. 2 ÅC. 1 mmD. 1 cm
• The energy of a photon is `E = hv` and the momentum of photon `p = (h)/(lambda)` , then the velocity of photon will beA. `E//p`B. `Ep`C. `((E)/(p))^(2)`D. `3 xx 10^(8) m//s`
• The momentum of a photon of energy `hv` will beA. `hv`B. `hv//c`C. `hvc`D. `h//v`
• If mean wavelength of light radiated by `100 W` lamp is `5000 Å` , then number of photons radiated per second areA. `3 xx 10^(23)`B. `2.5 xx 10^(22)`C. `2.5 xx 10^(20)`D. `5 xx 10^(17)`
• The figure shows different graphs between stopping potential `(V_(0))` and frequency `(v)` for photosensitive surface of cesium , potassium , sodium and lithium. The plots are parallel. Correct ranking of the targets according to their work function greatest forst will be A. (i) gt (ii) gt (iii) gt (iv)B. (i) gt (iii) gt (ii) gt (iv)C. (iv) gt (iii) gt (ii) lt (i)D. (i) = (iii) gt (ii) = (iv)
• The energy that should be added to an electron to reduce its de - Broglie wavelength from one `nm to 0.5 nm` isA. four times the initial energyB. equal to the initial energyC. twice the initial energyD. thrice the initial energy
• Energy of an quanta of frequency `10^(15) Hz` and `h = 6.6 xx 10^(-34) J - sec` will beA. `6.6 xx 10^(-19)J`B. `6.6 xx 10^(-12) J`C. `6.6 xx 10^(-49) J`D. `6.6 xx 10^(-41) J`
• When X rays pass through a strong uniform magnetic field. Then theyA. Do not get deflected at allB. Get deflected in the direction of the fieldC. Get deflected in the direction opposite to the fieldD. Get deflected in the direction perpendicular to the field
• If `lamda=10 Å` law for X-rays isA. Infra-redB. MicrowaveC. Ultra-violetD. X-rays
• X-rays of `lamda = 1Å` have frequencyA. `3 xx 10^(8) Hz`B. `3 xx 10^(18) Hz`C. `3 xx 10^(10) Hz`D. `3 xx 10^(15) Hz`