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The charge required for the reduction of `1 mol` `Cr_(2)O_(7)^(2-)` ions to `Cr^(3+)` isA. 96500CB. `2xx96500C`C. `3xx96500C`D. `6xx96500C`. |
Answer» Correct Answer - D `Cr_(2)O_(7)^(2-)+6e^(-)rarr2Cr^(3+)` Reduction of 1 mol of `Cr_(2)O_(7)^(2-),Cr^(3+)` required 6 m oles of electrons. |
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