The charge required for the reduction of `1 mol` `Cr_(2)O_(7)^(2-)` ions to `Cr^(3+)` isA. 1 FB. 2 FC. 6 FD. 4 F

The charge required for the reduction of `1 mol` `Cr_(2)O_(7)^(2-)` io

1.	The charge required for the reduction of `1 mol` `Cr_(2)O_(7)^(2-)` ions to `Cr^(3+)` isA. 1 FB. 2 FC. 6 FD. 4 F
Answer» `Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-) rarr 2Cr^(3+) +7H_(2)O` 1 mol `Cr_(2)O_(7)^(2-)` requires 6 mol of electrons, i.e., 6 Faraday charge

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The charge required for the reduction of `1 mol` `Cr_(2)O_(7)^(2-)` ions to `Cr^(3+)` isA. 1 FB. 2 FC. 6 FD. 4 F

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