The charge required for the reduction of 1 mole of `Cr_(2)O_(7)^(2-)` ions to `Cr^(3+)` isA. 96500 CB. `2xx96500 C`C. `3 xx96500 C`D. `6xx96500 C`

The charge required for the reduction of 1 mole of `Cr_(2)O_(7)^(2-)`

1.	The charge required for the reduction of 1 mole of `Cr_(2)O_(7)^(2-)` ions to `Cr^(3+)` isA. 96500 CB. `2xx96500 C`C. `3 xx96500 C`D. `6xx96500 C`
Answer» Correct Answer - D `overset(+6)(Cr_(2))overset(-2)(O_(7)) rarr overset(+3)(Cr)` Hence, electrons involved in this reduction will be `=2xx[(+6)-(+3)]=2xx3=6` `:.` Charge required for one mole `=6xx96500 C`

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The charge required for the reduction of 1 mole of `Cr_(2)O_(7)^(2-)` ions to `Cr^(3+)` isA. 96500 CB. `2xx96500 C`C. `3 xx96500 C`D. `6xx96500 C`

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