The circles x2+y2−6x+6y+17=0 and x2+y2−6x−2y+1=0, a common exterior tangent is drawn thus forming a curvilinear triangle.The radius of the circle inscribed in this triangle is

The circles x2+y2−6x+6y+17=0 and x2+y2−6x−2y+1=0, a common exter

1.	The circles x2+y2−6x+6y+17=0 and x2+y2−6x−2y+1=0, a common exterior tangent is drawn thus forming a curvilinear triangle.The radius of the circle inscribed in this triangle is
Answer» $T h e c i r c l e s x^{2} + y^{2} - 6 x + 6 y + 17 = 0 a n d x^{2} + y^{2} - 6 x - 2 y + 1 = 0, a c o m m o n e x t e r i o r t a n g e n t i s d r a w n t h u s f o r m i n g a c u r v i l i n e a r t r i a n g l e . T h e r a d i u s o f t h e c i r c l e i n s c r i b e d i n t h i s t r i a n g l e i s$

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The circles x2+y2−6x+6y+17=0 and x2+y2−6x−2y+1=0, a common exterior tangent is drawn thus forming a curvilinear triangle.The radius of the circle inscribed in this triangle is

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