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The circles x2+y2+kx+4y=20 and x2+y2+6x−8y+10=0 intersect orthogonally. Also circles x2+y2−p(x−y)+1=0 and p(x2+y2)+x−y=1 intersect orthogonally. Then kp equals

Answer»

The circles x2+y2+kx+4y=20 and x2+y2+6x8y+10=0 intersect orthogonally. Also circles x2+y2p(xy)+1=0 and p(x2+y2)+xy=1 intersect orthogonally. Then kp equals



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