The circuit shown in following figure contanis two diode `D_(1)` and `D_(2)` each with a forward resistance of `50 ohm` and with infinite backward resistance. If the battery voltage is `6V`, the current through the `100` ohm resistance (in amperes) is A. zeroB. `0.02`C. `0.03`D. `0.036`

The circuit shown in following figure contanis two diode `D_(1)` and `

1.	The circuit shown in following figure contanis two diode `D_(1)` and `D_(2)` each with a forward resistance of `50 ohm` and with infinite backward resistance. If the battery voltage is `6V`, the current through the `100` ohm resistance (in amperes) is A. zeroB. `0.02`C. `0.03`D. `0.036`
Answer» Correct Answer - B Accroding to the given polarity, diode `D_(1)` is forward biased while `D_(2)` is reverse biased. Hence current will pass through `D_(1)` only. so current `i=6/((150+50+100))=0.02 A`

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The circuit shown in following figure contanis two diode `D_(1)` and `D_(2)` each with a forward resistance of `50 ohm` and with infinite backward resistance. If the battery voltage is `6V`, the current through the `100` ohm resistance (in amperes) is A. zeroB. `0.02`C. `0.03`D. `0.036`

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