1.

The circular scale of a screw gauge has 50 divisions and pitch of 0.5 mm. Find the diameter of sphere. Main scale reading is 2.

Answer»

1.2 MM
1.25 mm
2.20 mm
2.25 mm

Solution :Least COUNT `=("PITCH")/("NUMBER of division on circuit scale")=0.5/50`
`=0.01 mm`
Now, diameter of ball `=(2xx0.5)+(2.5-5)(0.01)=1.2 mm`


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