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The circulation of blood in human body supplies `O_(2)` and releases `CO_(2)`. The concentration of `O_(2)` and `CO_(2)` is variable but on the average, 100 mL blood contains 0.02 g of `O_(2)` and 0.08 g of `CO_(2)`. Calculate the volume of `O_(2)` and `CO_(2)` at 1 atmosphere and body temperature of `37^(@)C` assuming 10 L of blood in human body. |
Answer» 100 mL blood contains `0.02 g O_(2)` and `0.08 g CO_(2)` `:.` 10 L=10,000 mL blood will contain `O_(2)=(0.02)/(100)xx10000=2g" and " CO_(2)=(0.08)/(100)xx10000=8g` `PV=nRT=(w)/(M)RT` `:. " For "O_(2)," "1xxV=(2)/(32)xx0.0821xx310 " or "V_(o_(2))=1.59 L` For `CO_(2), " " 1xxV=(8)/(44)xx0.0821xx310 " or "V_(CO_(2))=4.62 L` |
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