The circumference of a circle exceeds the diameter by 16.8 cm. Find th

1.	The circumference of a circle exceeds the diameter by 16.8 cm. Find the circumference of the circle.
Answer» Given : The circumference of a circle exceeds the diameter by 16.8 cm. To find : The circumference of the circle. Solution : Let diameter of circle = x cm So, acc. to given condition Circumference = x+16.8 cm Circumference of circle is 2πr. ⇒ 2πr = x + 16.8 Diameter = 2r ⇒ \(\frac{22}7\times{x} = x + 16.8\) ⇒ \(\frac{22}7{x} -x = 16.8\) ⇒ \(\frac{22x - 7x}7= 16.8\) ⇒ \(\frac{15x}7= 16.8\) ⇒ 15 x = 16.8 × 7 ⇒15 x = 117.6 ⇒ x = \(\frac{117.6}{15}\) ⇒ x = 7.84 Circumference= x + 16.8 (x = 2r) Circumference = 7.84 + 16.8 = 24.64 cm

The circumference of a circle exceeds the diameter by 16.8 cm. Find the circumference of the circle.

Answer»

Given :

The circumference of a circle exceeds the diameter by 16.8 cm.

To find :

The circumference of the circle.

Solution :

Let diameter of circle = x cm

So,

acc. to given condition

Circumference = x+16.8 cm

Circumference of circle is 2πr.

⇒ 2πr = x + 16.8

Diameter = 2r

⇒ \(\frac{22}7\times{x} = x + 16.8\)

⇒ \(\frac{22}7{x} -x = 16.8\)

⇒ \(\frac{22x - 7x}7= 16.8\)

⇒ \(\frac{15x}7= 16.8\)

⇒ 15 x = 16.8 × 7

⇒15 x = 117.6

⇒ x = \(\frac{117.6}{15}\)

⇒ x = 7.84

Circumference= x + 16.8 (x = 2r)

Circumference = 7.84 + 16.8 = 24.64 cm