The circumference of the second Bohr orbit of electron in hydrogen atom is `600nm` . The potential difference that must be applied between the plates so that the electron have the de Broglie wavelength corresponding in this circumference isA. `10^(-5) V`B. `(5)/(3)10^(-5) V`C. `5 xx 10^(-5) V`D. `3 xx10^(-5) V`

The circumference of the second Bohr orbit of electron in hydrogen ato

1.	The circumference of the second Bohr orbit of electron in hydrogen atom is `600nm` . The potential difference that must be applied between the plates so that the electron have the de Broglie wavelength corresponding in this circumference isA. `10^(-5) V`B. `(5)/(3)10^(-5) V`C. `5 xx 10^(-5) V`D. `3 xx10^(-5) V`
Answer» Correct Answer - D de Brogile wavelength of electron in hydrogen atom`= (h)/(mv) = (2 pi r_(n))/(n)` For second Bohr orbit, `lambda = (600 xx 10^(-9))/(2) = 3000 xx 10^(-9) m` `lambda = sqrt((150)/(V)) Å = 300 Å` `:. V = (150)/((3000)^(2)) = (5)/(3) xx 10^(-5) V`

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