The circumferences of circular faces of a frustum are 132 cm and 88 cm and its height is 24 cm. To find the curved surface area of the frustum complete the following activity.(π=227)circumference1 = 2πr1 = 132 r1 = 132π=134 circumference2 =2πr2= 88 r2= 882π=134slant height of frustum, l = h2 + r1 - r2212232 +1234 2= 1234 cmcurved surface area of the frustum = π (r1 + r2 ) l = π × 123 × 132= 123 sq.cm.

The circumferences of circular faces of a frustum are 132 cm and 88 cm

1.	The circumferences of circular faces of a frustum are 132 cm and 88 cm and its height is 24 cm. To find the curved surface area of the frustum complete the following activity.(π=227)circumference1 = 2πr1 = 132 r1 = 132π=134 circumference2 =2πr2= 88 r2= 882π=134slant height of frustum, l = h2 + r1 - r2212232 +1234 2= 1234 cmcurved surface area of the frustum = π (r1 + r2 ) l = π × 123 × 132= 123 sq.cm.
Answer» The circumferences of circular faces of a frustum are 132 cm and 88 cm and its height is 24 cm. To find the curved surface area of the frustum complete the following activity.( $π = \frac{22}{7}$ ) circumference₁ = 2 $π$ r₁= 132 r₁= $\frac{132}{π} = 134$ circumference₂ =2 $π$ r₂= 88 r₂= $\frac{88}{2 π} = 134$ slant height of frustum, l = $\sqrt{h^{2} + {(r_{1} - r_{2})}^{2}} \sqrt{1223^{2} + 1234^{2}} = 1234 cm$ curved surface area of the frustum = $π$ (r₁+ r₂ ) l = $π \times 123 \times 132 = 123 sq . cm .$

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