The co-efficient of friction between the floor and the body B is 0.1 The co-efficient of friction between the bodies BThe mass of A is m//2 and of B is m Which of the following statements are ture ? .

The co-efficient of friction between the floor and the body B is 0.1 T

1.	The co-efficient of friction between the floor and the body B is 0.1 The co-efficient of friction between the bodies BThe mass of A is m//2 and of B is m Which of the following statements are ture ? .
Answer» The bodies will move together if `F = 0.25mg` The body `A` will slip with respect to B if `F = 0.5mg` The bodies WILLBE at rest if `F = 0.5 mg` The maximum value of `F` for which the two bodies will move together is `0.45 mg` Solution :Here, mass of `B = m`, mass of `A = (m)/(2)` (a) Force of friction between `A` and `Bf_(1) = 0.2 ((m)/(2)) g = 0.1 mg` Force of friction between `B` and FLOOR `f_(2) = 0.1 (m + (m)/(2)) g = (0.3)/(2) mg = 0.15mg` The bodies will move together, if `F = f_(1) + f_(2) = 0.1 mg + 0.15mg = 0.25mg` If `F= 0.5mg` force between `A` and `B` will exceed `0.1mg` and the the body A will slip The bodies cannot move together when `F= 0.5mg` If `F =0.1mg` the bodies will be at rest as `Flt(f_(1) + f_(2))` The two bodies will move together till max accelerating force on `A = 0.1 mg = f_(1)` acceleration of `A = (0.1mg)/(m//2) = 0.2g` acceleration of `B = 0.2 g` max ACC. force on `B = m xx 0.2g = 0.2 mg` As `F_(2) =0.15mg` `:.` Maximum value of `F` for with `A` and `B` will move together = `0.1 mg + 0.1 mg + 0.2 mg + 0.15mg = 0.45mg` .