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The CO in a 20.3L sample of gas was converted to `CO_(2)` by passing the gas over iodine pentoxide heated to `150^(@)C` : `I_(2)O_(5)(s)+5CO(g)rarr5CO_(2)(g)+I_(2)(g)` The iodine distilled at this temperature and was collected in an absorber containing 8.25mL of `0.11101M Na_(2)S_(2)O_(3)` . The excess hypo was back-titrated with `2.16mL` of `0.00947M I_(2)` solution. The milligrams of `CO` in `1L` of the original gas sample was therefore:A. `0. 172mg`B. `0.283mg`C. `0.349mg`D. `0.506mg`

Answer» Correct Answer - a


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