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The co-ordinates of the points on the curve `y=x^(2)+3x+4` at which the tangent passes through the origin are(A) `(-2,14)`(B) `(2,14)`(C) `(2,-2)`(D) `(-2,2)`A. `(-2,14)`B. `(2,14)`C. `(2,-2)`D. `(-2,2)` |
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Answer» Correct Answer - B::D `(dy)/(dx)` at `x_(1),y_(1)` must equal to `(y_(1)-0)/(x_(1)-0)` Therefore `2x_(1)+3=(x_(1)^(2)+3x_(1)+4-0)/(x_(1)-0)` Hence `x_(1)^(2)=4impliesx_(1)=+-2impliesy_(1)=14,2` `(2,14),(-2,2)`s |
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