InterviewSolution
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InterviewSolution
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The coagulation of `100 mL` of a colloidal solution of gold is completely prevented by the addition of `0.030 g` of it before adding `1 mL` of `10% NaCl` solution. Find out the gold number of starch? |
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Answer» Correct Answer - 3 Haemoglobin added to 100 mL of gold sol to prevent coagulation by 1 mL of 10% NaCl sol=0.03g=30mg Haemoglobin requried to be added to 10mL of gold sol to prevent coagulation by 1mL of 10% NaCl sl=3mg. Therefore, gold number of gaemoglobin=3 |
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