1.

The coagulation of 200 mL of a positive colloid took place when 0.73 g HCl was added to it without changing the volume much. The flocculation value of HCl for the colloid is

Answer»

0.365
36.5
100
150

Solution :200mL of the SOL needs=0.02 mol=20m mol 1000 ML (1L) of the sol will REQUIRE
`=(20xx1000)/(200)=100` m mol.


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