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The coefficient of friction between a hemispherical bowl and an insect is `sqrt(0.44)` and the radius of the bowl is `0.6m`. The maximum height to which an insect can crawl in the bowl will be .A. `0.4m`B. `0.2m`C. `0.3m`D. `0.1m` |
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Answer» Correct Answer - D `h =r (1 -cos theta) =r [1 -(1)/(sqrt(mu_(s)^(2)+1))]` |
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