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The coefficient of mutual induction between primary and secondary coils is 2 H. Calculate the induced emf if a current of 4A is cut off in 2.5 × 10-4 second. |
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Answer» Data : M = 2 H, dI = – 4 A, dt = 2.5 × 10-4 s The induced emf, e = – M \(\cfrac{dI}{dt}\) = - \(\cfrac{2\times(-4)}{2.5\times10^{-4}}\) = \(\cfrac{8}{2.5}\) x 104 = 3.2 x 104 V |
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