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The coefficient of skeweness of a distribution is 0.85. If its mean is 3.4 more than its mode, find its variance. |
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Answer» Here, j = 0.85; x̄ = M0 + 3.4; s2 =? Now, j = \(\frac{\bar x−M_0}{s}\) ∴ 0.85 = \(\frac{M_o+3.4−M_o}{s}\) ∴ 0.85s = 3.4 ∴ s = \(\frac{3.4}{0.85}\) ∴ s = 4 Now, variance = s2 ∴ variance = (4)2 = 16 |
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