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The coefficient of skeweness of a distribution is 0.85. If its mean is 3.4 more than its mode, find its variance.

Answer»

Here, j = 0.85; x̄ = M0 + 3.4; s2 =?

Now, j = \(\frac{\bar x−M_0}{s}\)

∴ 0.85 = \(\frac{M_o+3.4−M_o}{s}\)

∴ 0.85s = 3.4

∴ s = \(\frac{3.4}{0.85}\)

∴ s = 4

Now, variance = s2

∴ variance = (4)2 = 16



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